ξ_{j}γ_{ij} = max_{k} ξ_{k}γ_{ik} vs. ξ_{j.}’γ_{i.} = max_{k} ξ_{k.}’γ_{i.}
That is the question. Ok, το βρήκα.
Ό,τι του κατέβει του καθενός
ξ_{j}γ_{ij} = max_{k} ξ_{k}γ_{ik} vs. ξ_{j.}’γ_{i.} = max_{k} ξ_{k.}’γ_{i.}
That is the question. Ok, το βρήκα.
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